Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 8 - Review Exercises - Page 950: 14

Answer

The matrix $ A+D $ is, $ A+D=\left[ \begin{array}{*{35}{l}} 0 & 2 & 3 \\ 8 & 1 & 3 \\ \end{array} \right]$

Work Step by Step

Here we need to find $ A+D $. Therefore consider, $\begin{align} & A+D=\left[ \begin{array}{*{35}{l}} 2 & -1 & 2 \\ 5 & 3 & -1 \\ \end{array} \right]+\left[ \begin{array}{*{35}{l}} -2 & 3 & 1 \\ 3 & -2 & 4 \\ \end{array} \right] \\ & =\left[ \begin{array}{*{35}{l}} 2-2 & -1+3 & 2+1 \\ 5+3 & 3-2 & -1+4 \\ \end{array} \right] \\ & =\left[ \begin{array}{*{35}{l}} 0 & 2 & 3 \\ 8 & 1 & 3 \\ \end{array} \right] \end{align}$ Thus, $ A+D=\left[ \begin{array}{*{35}{l}} 0 & 2 & 3 \\ 8 & 1 & 3 \\ \end{array} \right]$.
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