Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 7 - Section 7.6 - Linear Programming - Exercise Set - Page 871: 4


$z(0,0)= 0$, $z(0,9)= 405$, $z(4,4)= 300$, $z(3,0)= 90$ maximum $z(0,9)= 405$ minimum $z(0,0)= 0$

Work Step by Step

Step 1. Given the objective function $z(x,y)=30x+45y$, we can obtain the function values at each corner as $z(0,0)=30(0)+45(0)=0$ $z(0,9)=30(0)+45(9)=405$ $z(4,4)=30(4)+45(4)=300$, $z(3,0)=30(3)+45(0)=90$ Step 2. We can find the maximum of $z$ as $z(0,9)= 405$ Step 3. We can find the minimum of $z$ as $z(0,0)= 0$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.