## Precalculus (6th Edition) Blitzer

$z(3,2)= 13$, $z(4,10)= 32$, $z(5,12)= 39$, $z(8,6)= 36$, $z(7,4)= 29$, maximum $z(5,12)= 39$ minimum $z(3,2)= 13$
Step 1. Given the objective function $z(x,y)=3x+2y$, we can obtain the function values at each corner as $z(3,2)=3(3)+2(2)=13$, $z(4,10)=3(4)+2(10)=32$, $z(5,12)=3(5)+2(12)=39$, $z(8,6)=3(8)+2(6)=36$, $z(7,4)=3(7)+2(4)=29$, Step 2. We can find the maximum of $z$ as $z(5,12)= 39$ Step 3. We can find the minimum of $z$ as $z(3,2)= 13$