Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 7 - Section 7.6 - Linear Programming - Exercise Set - Page 871: 2


$z(3,2)= 13$, $z(4,10)= 32$, $z(5,12)= 39$, $z(8,6)= 36$, $z(7,4)= 29$, maximum $z(5,12)= 39$ minimum $z(3,2)= 13$

Work Step by Step

Step 1. Given the objective function $z(x,y)=3x+2y$, we can obtain the function values at each corner as $z(3,2)=3(3)+2(2)=13$, $z(4,10)=3(4)+2(10)=32$, $z(5,12)=3(5)+2(12)=39$, $z(8,6)=3(8)+2(6)=36$, $z(7,4)=3(7)+2(4)=29$, Step 2. We can find the maximum of $z$ as $z(5,12)= 39$ Step 3. We can find the minimum of $z$ as $z(3,2)= 13$
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