Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 7 - Section 7.4 - Systems of Nonlinear Equations in Two Variables - Exercise Set - Page 851: 50


$(-5,0)$, $(-3,18)$, $(3,72)$

Work Step by Step

Here, we have $-9x+(x^3+5x^2)=45$ and, $x^3+5x^2-9x-45=0$ Now, $(x+5)(x+3)(x-3)=24$ when $x=-5$ then we have $y=0$ when $x=-3$ then we have $y=18$ when $x=3$ then we have $y=72$ Hence, our answers are: $(-5,0)$, $(-3,18)$, $(3,72)$
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