Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 7 - Section 7.4 - Systems of Nonlinear Equations in Two Variables - Exercise Set - Page 851: 43


$(4,6)$, $(6,4)$

Work Step by Step

We have $x+y=10$ and, $xy=24$ Now, $x(10-x)=24$ or, $x^2-10x+24=0$ Thus, we have $(x-4)(x-6)=0$ when $x=4$ then we have $y=6$ when $x=6$ then we have $y=4$ Hence, our answers are: $(4,6)$, $(6,4)$
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