## Precalculus (6th Edition) Blitzer

$(4,6)$, $(6,4)$
We have $x+y=10$ and, $xy=24$ Now, $x(10-x)=24$ or, $x^2-10x+24=0$ Thus, we have $(x-4)(x-6)=0$ when $x=4$ then we have $y=6$ when $x=6$ then we have $y=4$ Hence, our answers are: $(4,6)$, $(6,4)$