#### Answer

See graph.
$(0,-3)$ and $(2,-1)$

#### Work Step by Step

Step 1. See graph.
Step 2. The two intersection points can be found as $(0,-3)$ and $(2,-1)$
Step 3. Plug-in the coordinates into the first equation; we have $0-(-3)=3$ and $2-(-1)=3$ showing that both points are on the line.
Step 4. Plug-in the coordinates into the second equation:
$(0-2)^2+(-3+3)^2=4$ and $(2-2)^2+(-1+3)^2=4$
showing that both points are on the circle.