Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 7 - Section 7.3 - Partial Fractions - Exercise Set - Page 842: 61

Answer

It does not make sense.

Work Step by Step

$\frac{p\left( x \right)}{q\left( x \right)}$ Where $\text{degree of }p>\text{degree of }q$ $\frac{p\left( x \right)}{q\left( x \right)}$ Where, both $p\left( x \right)$ and $q\left( x \right)$ are polynomials and the degree of $p\left( x \right)$ is smaller then the degree of $q\left( x \right)$; partial fractions can only be done if the degree of the numerator is strictly less then the degree of the denominator . Thus, if the degree of $p\left( x \right)$ is grater than the degree of $q\left( x \right)$, then it does not make sense.
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