Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 7 - Section 7.2 - Systems of Linear Equations in Three Variables - Exercise Set - Page 832: 57


a. maximum height $ 55\ ft$, $x= 100\ ft$ b. $204.9\ ft$

Work Step by Step

a. With the given equation $f(x) = -0.005x^2 + x + 5$, we have $a=-0.005, b=1$ and the maximum height happens at $x=-\frac{b}{2a}=-\frac{1}{-0.01}=100\ ft$ and the maximum height is $f(100)=-0.005(100)^2 + (100) + 5=55\ ft$ b. The travel distance can be found by letting $f(x)=0$: $ -0.005x^2 + x + 5=0$ which can be solved using a formula or graphically to get $x\approx204.9\ ft$ as shown in the figure.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.