Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 7 - Section 7.2 - Systems of Linear Equations in Three Variables - Exercise Set - Page 832: 57

Answer

a. maximum height $ 55\ ft$, $x= 100\ ft$ b. $204.9\ ft$
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Work Step by Step

a. With the given equation $f(x) = -0.005x^2 + x + 5$, we have $a=-0.005, b=1$ and the maximum height happens at $x=-\frac{b}{2a}=-\frac{1}{-0.01}=100\ ft$ and the maximum height is $f(100)=-0.005(100)^2 + (100) + 5=55\ ft$ b. The travel distance can be found by letting $f(x)=0$: $ -0.005x^2 + x + 5=0$ which can be solved using a formula or graphically to get $x\approx204.9\ ft$ as shown in the figure.
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