Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 7 - Cumulative Review Exercises - Page 880: 40

Answer

The value of b to the nearest tenth is $92.9$.

Work Step by Step

By using the sine rule, $\begin{align} & \frac{\sin {{12}^{{}^\circ }}}{20}=\frac{\sin {{75}^{{}^\circ }}}{b} \\ & b=\frac{20\times \sin {{75}^{{}^\circ }}}{\sin {{12}^{{}^\circ }}} \\ & b=\frac{20\times 0.96}{0.20} \\ & b\approx 92.8 \end{align}$ Hence, b is approximately $92.9$.
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