## Precalculus (6th Edition) Blitzer

The solution of the given equation is $\underline{\left( 1,7 \right)}$
We simplify the inequality further to obtain the value of x: \begin{align} & \frac{x+5}{x-1}\gt2 \\ & x+5\gt2x-2 \\ & -x\gt-7 \\ & x\lt7 \end{align} For $x=1$, $\frac{x+5}{x-1}$ is undefined as the denominator becomes zero. To make the left hand side positive, the value of x should be greater than 1. Hence, $x\gt1$ The solution of the given equation is $\underline{\left( 1,7 \right)}$