Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 6 - Test - Page 800: 22


The magnitude of the work done is $1966\text{ foot-pounds}$.

Work Step by Step

The wagon handle makes an angle of $35{}^\circ $ with the road. Hence, the work-done is: $ W=\left\| \mathbf{F} \right\|\left\| \mathbf{d} \right\|\cos \theta $ ……(1) Where, $\left\| \mathbf{F} \right\|=40\text{ pounds}$, $\left\| \mathbf{d} \right\|=60\text{ feet}$ and $\theta =35{}^\circ $. Now put it in equation (1), $\begin{align} & W=\left( 40 \right)\left( 60 \right)\cos 35{}^\circ \\ & =2400\left( 0.8191 \right) \\ & =1965.84 \\ & \approx 1966\text{ foot-pounds} \end{align}$
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