Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 6 - Test - Page 800: 1

Answer

The value of $ b $ to the nearest tenth is $8.0$.

Work Step by Step

As the angle $ B $ is provided, so, by using the Law of Sines to find $ b $, we get: $\begin{align} & \frac{b}{\sin B}=\frac{a}{\sin A} \\ & \frac{b}{\sin 68{}^\circ }=\frac{4.8}{\sin 34{}^\circ } \\ & b=\frac{4.8\sin 68{}^\circ }{\sin 34{}^\circ } \\ & \approx 8.0 \end{align}$ Hence, the value of $ b $ is 8.0
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