## Precalculus (6th Edition) Blitzer

The value of $b$ to the nearest tenth is $8.0$.
As the angle $B$ is provided, so, by using the Law of Sines to find $b$, we get: \begin{align} & \frac{b}{\sin B}=\frac{a}{\sin A} \\ & \frac{b}{\sin 68{}^\circ }=\frac{4.8}{\sin 34{}^\circ } \\ & b=\frac{4.8\sin 68{}^\circ }{\sin 34{}^\circ } \\ & \approx 8.0 \end{align} Hence, the value of $b$ is 8.0