#### Answer

The slopes of the provided two lines are equal.

#### Work Step by Step

If the slopes of two lines are equal then the lines are parallel to each other.
The slope $\left( m \right)$ of the line passing through the two points $\left( {{x}_{1}},{{x}_{2}} \right)\text{ and }\left( {{y}_{1}},{{y}_{2}} \right)$ is given by:
$m=\frac{{{y}_{2}}-{{y}_{1}}}{{{x}_{2}}-{{x}_{1}}}$.
The slope of the first line passing through the point $\left( -3,-3 \right)$ and $\left( 0,3 \right)$ is:
$\begin{align}
& {{m}_{1}}=\frac{{{y}_{2}}-{{y}_{1}}}{{{x}_{2}}-{{x}_{1}}} \\
& =\frac{3-\left( -3 \right)}{0-\left( -3 \right)} \\
& =\frac{6}{3} \\
& =2
\end{align}$
So, the slope of the first line is $2$
The slope of the second line passing through $\left( 0,0 \right)$ and $\left( 3,6 \right)$ is
$\begin{align}
& {{m}_{2}}=\frac{{{y}_{2}}-{{y}_{1}}}{{{x}_{2}}-{{x}_{1}}} \\
& =\frac{0-\left( -6 \right)}{0-\left( -3 \right)} \\
& =\frac{6}{3} \\
& =2
\end{align}$
Thus, the slope of the second line is also $2$.