Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 6 - Section 6.5 - Complex Numbers in Polar Form; DeMoivre's Theorem - Exercise Set - Page 767: 37

Answer

The multiplication of the complex numbers in the polar form is $30\left( \cos 70{}^\circ +i\sin 70{}^\circ \right)$.

Work Step by Step

Here, $\begin{align} & {{z}_{1}}=6\left( \cos 20{}^\circ +i\sin 20{}^\circ \right) \\ & {{z}_{2}}=5\left( \cos 50{}^\circ +i\sin 50{}^\circ \right) \\ \end{align}$ Therefore, $\begin{align} & {{z}_{1}}\times {{z}_{2}}=6\times 5\left( \cos \left( 20{}^\circ +50{}^\circ \right)+i\sin \left( 20{}^\circ +50{}^\circ \right) \right) \\ & =30\left( \cos 70{}^\circ +i\sin 70{}^\circ \right) \end{align}$ The multiplication of the complex numbers in the polar form is $30\left( \cos 70{}^\circ +i\sin 70{}^\circ \right)$
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