Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 6 - Section 6.2 - The Law of Cosines - Exercise Set - Page 732: 74


$(x+3)^2+y^2=9$ $C(-3,0)$, $r=3$ See graph.

Work Step by Step

Step 1. Rewrite the equation of the circle as $x^2+6x+9 +y^2=9$ or $(x+3)^2+y^2=9$ Step 2. We can identify the center as $C(-3,0)$ and radius as $r=3$ Step 3. See graph.
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