Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 6 - Section 6.2 - The Law of Cosines - Exercise Set - Page 732: 60


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Work Step by Step

The Law of Cosines gives $c^2=a^2+b^2-2ab\ cosC$ In the case of a right triangle $C=90^\circ$, we have $cosC=0$ and the Law of Cosines becomes $c^2=a^2+b^2$, which is the Pythagorean Theorem. Thus, the Pythagorean Theorem is a special case of the Law of Cosines.
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