Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 6 - Cumulative Review Exercises - Page 801: 15


a. $4\ m$ b. $\frac{5}{2\pi}\ Hz$ c. $\frac{2\pi}{5}\ sec$

Work Step by Step

a. Given the motion equation $d=4sin(5t)$, we can get the maximum displacement as the amplitude $A=4\ m$ b. The frequency $f$ can be found in the relation $\omega=2\pi f=5$. Thus $f=\frac{5}{2\pi}\ Hz$ c. The time required for one cycle is the period, which is given by $p=\frac{1}{f}=\frac{2\pi}{5}\ sec$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.