Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 6 - Cumulative Review Exercises - Page 801: 14

Answer

$1.5\ sec$, $44\ ft$

Work Step by Step

Step 1. Based on the given equatioin, we have $a=-16,b=48$ Step 2. The maximum will happen when $t=-\frac{b}{2a}=-\frac{48}{2(-16)}=1.5\ sec$ Step 3. We can get the maximum height as $s(1.5)=-16(1.5)^2+48(1.5)+8=44\ ft$
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