Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 5 - Section 5.5 - Trigonometric Equations - Exercise Set - Page 706: 167

Answer

The value of $B$ is $31.5\text{ }\!\!{}^\circ\!\!\text{ }$.

Work Step by Step

On solving the provided expression for B: $\begin{align} & \frac{81}{\sin 43\text{ }\!\!{}^\circ\!\!\text{ }}=\frac{62}{\sin B} \\ & \sin B=\frac{62\times \sin 43\text{ }\!\!{}^\circ\!\!\text{ }}{81} \end{align}$ $\sin 46\text{ }\!\!{}^\circ\!\!\text{ }=0.68199836$ Use this value in the above expression to get $\begin{align} & \sin B=\frac{62\times 0.68199836}{81} \\ & =\frac{42.283898}{81} \\ & =0.52202 \end{align}$ Then, take sine on the right side and find the value. $B={{\sin }^{-1}}\left( 0.52202 \right)$ ${{\sin }^{-1}}\left( 0.52202 \right)=31.46807$ Round off to the nearest decimal. $B=31.5\text{ }\!\!{}^\circ\!\!\text{ }$
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