Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 5 - Section 5.5 - Trigonometric Equations - Exercise Set - Page 706: 163


The value of $\tan \frac{4\pi }{3}$ is $\sqrt{3}$.

Work Step by Step

$\frac{4\pi }{3}$ lies in the third quadrant. So, the reference angle is $\frac{\pi }{3}$. $\tan \frac{4\pi }{3}=\tan \left( \pi +\frac{\pi }{3} \right)$ As $\tan \left( \pi +\frac{\pi }{3} \right)=\tan \frac{\pi }{3}$. So, $\begin{align} & \tan \frac{4\pi }{3}=\tan \frac{\pi }{3} \\ & \tan \frac{4\pi }{3}=\sqrt{3} \\ \end{align}$
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