Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 5 - Section 5.4 - Product-to-Sum and Sum-to-Product Formulas - Exercise Set - Page 689: 35

Answer

a. $y=-cot(2x)$ b. See explanations.

Work Step by Step

a. It appears that the function $y=-cot(2x)$ gives the same graph. b. Using the sum to product formula, we have $sin(x)-sin(3x)=2cos(\frac{x+3x}{2})sin(\frac{x-3x}{2})=-2cos(2x) sin(x)$ and $cos(x)-cos(3x)=-2sin(\frac{x+3x}{2}) sin(\frac{x-3x}{2})=2sin(2x) sin(x)$ Thus we have $y=\frac{sin(x)-sin(3x)}{cos(x)-cos(3x)}=\frac{-2cos(2x) sin(x)}{2sin(2x) sin(x)}=-cot(2x)$
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