Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 5 - Section 5.4 - Product-to-Sum and Sum-to-Product Formulas - Exercise Set - Page 689: 24

Answer

Please see below.

Work Step by Step

We verify as below: $$\frac{\sin 3x + \sin x }{\cos 3x + \cos x}= \frac{2\sin \frac{3x+x}{2}\cos \frac{3x-x}{2}}{\cos \frac{3x+x}{2} \cos \frac{3x-x}{2}} \\ =\frac{\sin 2x \cos x }{\cos 2x \cos x}=\tan 2x$$
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