## Precalculus (6th Edition) Blitzer

$6 \sin \pi t$
Amplitude, $A=|6|=6$ Now, $f=\dfrac{\omega}{2 \pi} \implies \omega =2 \pi f$ So, $\omega =2 \pi (1/2)=\pi$ period, $P=\dfrac{2 \pi}{\omega}$ So, $d=A \sin \omega t=6 \sin \pi t$