Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Section 4.8 - Applications of Trigonometric Functions - Exercise Set - Page 639: 54

Answer

$13.3$ miles

Work Step by Step

Since, $\tan \theta= \dfrac{Opposite}{Adjacent}$ $\tan (90-34)^{\circ}= \dfrac{h}{9} $ Solve for $h$: $ h=9 \tan (90-34)^{\circ} =13.3$ miles
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