## Precalculus (6th Edition) Blitzer

Amplitude $=10$ and Period $=12$
We are given the function: $y=10 \cos (\dfrac{\pi}{6})$ Since, Amplitude $=|10|=10$ Also, Period is: $P=\dfrac{2 \pi}{(\pi/6)}=12$ Therefore, Amplitude $=10$ and Period $=12$