Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Section 4.7 - Inverse Trigonometric Functions - Exercise Set - Page 629: 129


Amplitude $=10$ and Period $=12$

Work Step by Step

We are given the function: $ y=10 \cos (\dfrac{\pi}{6})$ Since, Amplitude $=|10|=10$ Also, Period is: $ P=\dfrac{2 \pi}{(\pi/6)}=12$ Therefore, Amplitude $=10$ and Period $=12$
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