Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Section 4.7 - Inverse Trigonometric Functions - Exercise Set - Page 629: 127


$ a \approx 4.96$ and $ c \approx 13.07$

Work Step by Step

$\tan A=\dfrac{a}{b}$ $\implies a=b \tan A=(12.1) \times \tan 22.3^{\circ}$ So, $ a \approx 4.96$ Now, $ c=\dfrac{a}{\sin A}$ $\implies c=\dfrac{4.96}{\sin 22.3^{\circ}}$ So, $ c \approx 13.07$
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