## Precalculus (6th Edition) Blitzer

$a \approx 4.96$ and $c \approx 13.07$
$\tan A=\dfrac{a}{b}$ $\implies a=b \tan A=(12.1) \times \tan 22.3^{\circ}$ So, $a \approx 4.96$ Now, $c=\dfrac{a}{\sin A}$ $\implies c=\dfrac{4.96}{\sin 22.3^{\circ}}$ So, $c \approx 13.07$