Answer
$$\log_bx+ \frac{1}{3}\log_b y$$
Work Step by Step
We expand the log as follows:
$$\log_b(x \sqrt[3]{y})=\log_bx + \log_by^{\frac{1}{3}}=\log_bx+ \frac{1}{3}\log_b y$$
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter 4 - Section 4.7 - Inverse Trigonometric Functions - Exercise Set - Page 628: 124
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