Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Section 4.7 - Inverse Trigonometric Functions - Exercise Set - Page 628: 124

Answer

$$\log_bx+ \frac{1}{3}\log_b y$$

Work Step by Step

We expand the log as follows: $$\log_b(x \sqrt[3]{y})=\log_bx + \log_by^{\frac{1}{3}}=\log_bx+ \frac{1}{3}\log_b y$$
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