Answer
No.
Work Step by Step
We need to consider the domain and range restrictions on $sin^{-1}x$; thus we have $sin^{-1}(sin\frac{5\pi}{6})=sin^{-1}(sin\frac{\pi}{6})=\frac{\pi}{6}$. So the answer is no.
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter 4 - Section 4.7 - Inverse Trigonometric Functions - Exercise Set - Page 628: 107
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
