Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Section 4.7 - Inverse Trigonometric Functions - Exercise Set - Page 627: 93

Answer

$0.408, 0.602,0.654,0.645,0.613$

Work Step by Step

In order to get the values for $\theta $, we need to substitute the values into $ x $. when $ x =5 \implies \theta =0.408$; when $ x =10 \implies \theta =0.602$ ; when $ x =15 \implies \theta =0.654$; when $ x =20 \implies \theta =0.645$; when $ x =25 \implies \theta =0.613$ Therefore, we have $0.408, 0.602,0.654,0.645,0.613$
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