Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Section 4.7 - Inverse Trigonometric Functions - Exercise Set - Page 627: 81

Answer

$(1,3]$ and Range: $[-\pi,0]$

Work Step by Step

A phase shift of $2$ results in shifting the domain of the sine curve right by $2$ and a vertical shift of $-\dfrac{\pi}{2}$ results in shifting the range of the curve down by an angle of $\dfrac{\pi}{2}$. Therefore, we have the Domain and Range of the function as follows: Domain : $(1,3]$ and Range: $[-\pi,0]$
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