Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Section 4.7 - Inverse Trigonometric Functions - Exercise Set - Page 626: 31

Answer

$0.9$

Work Step by Step

Suppose $\theta =\sin^{-1}(0.9)$ This gives: $\sin \theta=\sin [\sin^{-1}(0.9)]$ The inverse property states that $\sin(\sin^{-1} a)=a $ satisfies for every $ a $ in the range $[-1,1]$ . Therefore, we have $ \sin [\sin^{-1}(0.9)]=0.9$
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