Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Section 4.7 - Inverse Trigonometric Functions - Exercise Set - Page 626: 11



Work Step by Step

Suppose $\theta = \cos^{-1} (0)$ This gives: $\cos \theta=0$ Now, $\theta = \cos^{-1} (0)=\dfrac{\pi}{2}$ Therefore, $\cos^{-1} (0)=\dfrac{\pi}{2}$
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