Answer
$-\dfrac{\pi}{3}$
Work Step by Step
Suppose $\theta = \tan^{-1} (-\sqrt 3)$
This gives: $\tan \theta=-\sqrt 3$
Now, $\theta = \tan^{-1} (-\sqrt 3)=-\dfrac{\pi}{3}$
Therefore, $\tan^{-1} (-\sqrt 3)=-\dfrac{\pi}{3}$
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