Answer
$[-\frac{\pi}{2}, \frac{\pi}{2}]$.
Work Step by Step
Here $x$ should be in the restricted domain of $sin(x)$; thus the answer is $[-\frac{\pi}{2}, \frac{\pi}{2}]$.
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter 4 - Section 4.7 - Inverse Trigonometric Functions - Concept and Vocabulary Check - Page 626: 7
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