Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Section 4.7 - Inverse Trigonometric Functions - Concept and Vocabulary Check - Page 626: 2

Answer

$[0,\pi]$, $cos^{-1}(x)$.

Work Step by Step

To have an inverse, a function needs to pass the horizontal line test. For $y=cos(x)$, we need to restrict the domain so that an inverse can be found, and the restricted domain is $[0,\pi]$. We use a special symbol $f^{-1}$ to denote an inverse, and the inverse of $y=cos(x)$ is $y=cos^{-1}(x)$.
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