Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Section 4.6 - Graphs of Other Trigonometric Functions - Exercise Set - Page 609: 2

Answer

$y=tan(x+\frac{\pi}{2})$

Work Step by Step

The period of $y=tan(x)$ is $\pi$; thus $tan(x-\frac{\pi}{2})=tan(x+\frac{\pi}{2}-\pi)=tan(x+\frac{\pi}{2})$. We can identify that the graph fits the equation $y=tan(x+\frac{\pi}{2})$
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