## Precalculus (6th Edition) Blitzer

$y=cot(x+\frac{\pi}{2})$.
The function $y=cot(x+\frac{\pi}{2})$ shifts the original $y=cot(x)$ to the left by $\frac{\pi}{2}$ and gives the graph in this case. Thus the answer is $y=cot(x+\frac{\pi}{2})$.