Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Section 4.5 - Graphs of Sine and Cosine Functions - Exercise Set - Page 595: 3


The amplitude of the function is $\frac{1}{3}$.

Work Step by Step

We have the trigonometric function $y=\frac{1}{3}\sin x$ The amplitude is the maximum value of function. The maximum value of the given trigonometric function is $\frac{1}{3}$. So, the amplitude of the trigonometric function is $\frac{1}{3}$. The period of the trigonometric function is $2\pi $. The quarter period is $\frac{2\pi }{4}$ or $\frac{\pi }{2}$. The cycle begins at $x=0$. Add quarter periods to find out the key points. First key point is ${{x}_{1}}=0$ Second key point is $\begin{align} & {{x}_{2}}=0+\frac{\pi }{2} \\ & =\frac{\pi }{2} \end{align}$ Third key point is $\begin{align} & {{x}_{3}}=\frac{\pi }{2}+\frac{\pi }{2} \\ & =\pi \end{align}$ Fourth key point is $\begin{align} & {{x}_{4}}=\pi +\frac{\pi }{2} \\ & =\frac{3\pi }{2} \end{align}$ Fifth key point is $\begin{align} & {{x}_{5}}=\frac{3\pi }{2}+\frac{\pi }{2} \\ & =2\pi \end{align}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.