#### Answer

Please see below.

#### Work Step by Step

Please note that a sine function $y=A\sin Bx$ has amplitude $|A|$ and period $\frac{2\pi }{B}$.
So the function $y=-\sin \frac{2}{3} x$ has amplitude $|-1|=1$ and period $\frac{2\pi }{\frac{2}{3} }=3\pi$.