## Precalculus (6th Edition) Blitzer

The ship is approx $357\text{ feet}$ from the lighthouse and the plane is approx $394\text{ feet}$ above the water.
Let us assume a = distance of the ship from the lighthouse. $\tan {{35}^{0}}=\frac{250}{a}\approx 357$ And the ship is approximately 357 feet from the lighthouse. Let b = plane's height above the lighthouse \begin{align} & \tan {{22}^{0}}=\frac{357}{b} \\ & b=357\tan {{22}^{0}}=357\left( 0.404 \right)\approx 144 \\ & 144+357=394 \end{align} Thus, the plane is approximately $394feet$ above the water.