Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Section 4.3 - Right Triangle Trigonometry - Exercise Set - Page 563: 80


The ship is approx $357\text{ feet}$ from the lighthouse and the plane is approx $394\text{ feet}$ above the water.

Work Step by Step

Let us assume a = distance of the ship from the lighthouse. $\tan {{35}^{0}}=\frac{250}{a}\approx 357$ And the ship is approximately 357 feet from the lighthouse. Let b = plane's height above the lighthouse $\begin{align} & \tan {{22}^{0}}=\frac{357}{b} \\ & b=357\tan {{22}^{0}}=357\left( 0.404 \right)\approx 144 \\ & 144+357=394 \end{align}$ Thus, the plane is approximately $394feet$ above the water.
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