Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Section 4.3 - Right Triangle Trigonometry - Exercise Set - Page 563: 75


The statement is true.

Work Step by Step

The above statement can be explained by using the trigonometric identity $1+{{\tan }^{2}}x={{\sec }^{2}}x$. After putting the value of $x={{15}^{0}}$ and rearranging the equation, we get: ${{\tan }^{2}}{{15}^{0}}$ $-{{\sec }^{2}}{{15}^{0}}$ is $-1$.
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