Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Section 4.2 - Trigonometric Functions: The Unit Circle - Exercise Set - Page 549: 99


The statement does not make sense.

Work Step by Step

From the property of the cosine function, $\cos \left( -\theta \right)=\cos \theta $ The value of $\cos \frac{\pi }{6}$ is $\cos \frac{\pi }{6}=\frac{\sqrt{3}}{2}$ Thus, the value of $\cos \left( -\frac{\pi }{6} \right)$ is $\frac{\sqrt{3}}{2}$. So, the statement is false.
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