Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Review Exercises - Page 645: 46

Answer

$\sin (-90^{\circ})=-1 \\ \cos (-90^{\circ})=0$ ; $\tan (-90^{\circ})=$ Not defined and $\csc (-90^{\circ})=-1$; $\sec (-90^{\circ})=$ Not defined ; $\cot (-90^{\circ})=0$

Work Step by Step

Here, the angle with $(0,-1)$ as a terminal point is: $-90^{\circ}=-270^{\circ}$ The Trigonometric functions are as follows: $\sin (-90^{\circ})=-1 \\ \cos (-90^{\circ})=0$ ; $\tan (-90^{\circ})=$ Not defined and $\csc (-90^{\circ})=-1$; $\sec (-90^{\circ})=$ Not defined ; $\cot (-90^{\circ})=0$
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