## Precalculus (6th Edition) Blitzer

$551.9$ feet
The trigonometric ratios are as follows: $\sin \theta= \dfrac{opposite}{hypotenuse}$ ; $\cos \theta= \dfrac{Adjacent}{hypotenuse}$ and $\tan \theta= \dfrac{Opposite}{Adjacent}$ We can use the sine and cosine of the triangle to solve for the distance. Since, $\sin 6^{\circ}= \dfrac{h}{5280}$ Now, $h =5280 \sin 6^{\circ}=551.9$ feet