Answer
$2$
Work Step by Step
Since, $\sin^2 \theta +\cos^2 \theta=1$
Here, $\theta = \dfrac{\pi}{2}$ and $\theta = \pi $
Thus, we have
$\sin^2 (\dfrac{\pi}{2}) -\cos^2 \pi =1-(-1)=2$
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter 4 - Mid-Chapter Check Point - Page 578: 25
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