Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 3 - Section 3.3 - Properties of Logarithms - Exercise Set - Page 477: 138


$$x=\frac{7 \pm \sqrt{61}}{2}$$

Work Step by Step

We solve the polynomial: $$x(x-7)=3 \quad \Rightarrow \quad x^2-7x-3=0 \quad \Rightarrow \quad x= \frac{-(-7) \pm \sqrt{(-7)^2-4(-3)(1)}}{2(1)} \quad \Rightarrow \quad x= \frac{7 \pm \sqrt{61}}{2}$$
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