Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 3 - Section 3.3 - Properties of Logarithms - Exercise Set - Page 477: 131



Work Step by Step

By applying the quotient rule and the identity $b^{\log_bM}=M$, we have$$e^{\ln 8x^5- \ln 2x^2}=e^{\ln \left ( \frac{8x^5}{2x^2} \right )}=\frac{8x^5}{2x^2}=4x^3.$$
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