Answer
$$4x^3$$
Work Step by Step
By applying the quotient rule and the identity $b^{\log_bM}=M$, we have$$e^{\ln 8x^5- \ln 2x^2}=e^{\ln \left ( \frac{8x^5}{2x^2} \right )}=\frac{8x^5}{2x^2}=4x^3.$$
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter 3 - Section 3.3 - Properties of Logarithms - Exercise Set - Page 477: 131
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