Answer
$-3$
Work Step by Step
RECALL:
$\log_b{b^x} = x.$
Note that
$\dfrac{1}{8}=\dfrac{1}{2^3} = 2^{-3}.$
Thus, the given expression can be written as
$\log_2{2^{-3}}.$
Use the rule above t obtain
$-3.$
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.