Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 3 - Section 3.2 - Exponential Functions - Exercise Set: 30

Answer

$\dfrac{1}{2}$

Work Step by Step

RECALL: $\log_b{b^x} = x.$ Note that $\sqrt{6}=6^{\frac{1}{2}}.$ Thus, the given expression can be written as $\log_6{6^{\frac{1}{2}}}.$ Use the rule above to obtain $\dfrac{1}{2}.$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.