## Precalculus (6th Edition) Blitzer

$f(x)=(0.8)^{x}=(\frac{4}{5})^{x}$ $(-4,\frac{625}{256})$,$(-2,\frac{25}{16})$,$(-1,\frac{5}{4})$,$(1,\frac{4}{5})$,$(2,\frac{16}{25})$,$(4,\frac{256}{625})$ Graph is attached
$f(x)=(0.8)^{x}=(\frac{4}{5})^{x}$ Lets put $x=-4,-2,-1,1,2,4$ $f(-4) = (\frac{4}{5})^{-4} = \frac{625}{256}$ $f(-2) = (\frac{4}{5})^{-2} = \frac{25}{16}$ $f(-1) = (\frac{4}{5})^{-1} = \frac{5}{4}$ $f(1) = (\frac{4}{5})^{1} = \frac{4}{5}$ $f(2) = (\frac{4}{5})^{2} = \frac{16}{25}$ $f(4) = (\frac{4}{5})^{4} = \frac{256}{625}$ Plot the set of points